获取旧历几月几日的js代码

获取旧历几月几日的js代码

作者:admin 时间:2017-08-02 分类:代码 评论:5 条 浏览:913
var DateUtil = function() {

  /**

   * 获取旧历几月几日

   * d : date对象

   * showYear: 是否显示农历年

   */
  this.getLunarDay = function(d, showYear) {
    var CalendarData = new Array(100);
    var madd = new Array(12);
    var tgString = "甲乙丙丁戊己庚辛壬癸";
    var dzString = "子丑寅卯辰巳午未申酉戌亥";
    var numString = "一二三四五六七八九十";
    var monString = "正二三四五六七八九十冬腊";
    var sx = "鼠牛虎兔龙蛇马羊猴鸡狗猪";
    var cYear, cMonth, cDay, TheDate;
    CalendarData = new Array(0xA4B, 0x5164B, 0x6A5, 0x6D4, 0x415B5, 0x2B6, 0x957, 0x2092F, 0x497, 0x60C96, 0xD4A, 0xEA5, 0x50DA9, 0x5AD, 0x2B6, 0x3126E, 0x92E, 0x7192D, 0xC95, 0xD4A, 0x61B4A, 0xB55, 0x56A, 0x4155B, 0x25D, 0x92D, 0x2192B, 0xA95, 0x71695, 0x6CA, 0xB55, 0x50AB5, 0x4DA, 0xA5B, 0x30A57, 0x52B, 0x8152A, 0xE95, 0x6AA, 0x615AA, 0xAB5, 0x4B6, 0x414AE, 0xA57, 0x526, 0x31D26, 0xD95, 0x70B55, 0x56A, 0x96D, 0x5095D, 0x4AD, 0xA4D, 0x41A4D, 0xD25, 0x81AA5, 0xB54, 0xB6A, 0x612DA, 0x95B,
      0x49B, 0x41497, 0xA4B, 0xA164B, 0x6A5, 0x6D4, 0x615B4, 0xAB6, 0x957, 0x5092F,
      0x497, 0x64B, 0x30D4A, 0xEA5, 0x80D65, 0x5AC, 0xAB6, 0x5126D, 0x92E, 0xC96, 0x41A95, 0xD4A, 0xDA5, 0x20B55, 0x56A, 0x7155B, 0x25D, 0x92D, 0x5192B, 0xA95, 0xB4A, 0x416AA, 0xAD5, 0x90AB5, 0x4BA, 0xA5B, 0x60A57, 0x52B, 0xA93, 0x40E95);
    madd[0] = 0;
    madd[1] = 31;
    madd[2] = 59;
    madd[3] = 90;
    madd[4] = 120;
    madd[5] = 151;
    madd[6] = 181;
    madd[7] = 212;
    madd[8] = 243;
    madd[9] = 273;
    madd[10] = 304;
    madd[11] = 334;

    function GetBit(m, n) {
      return (m >> n) & 1;
    }

    function e2c() {
      TheDate = (arguments.length != 3) ? new Date() : new Date(arguments[0], arguments[1], arguments[2]);
      var total, m, n, k;
      var isEnd = false;
      var tmp = TheDate.getFullYear();
      total = (tmp - 1921) * 365 + Math.floor((tmp - 1921) / 4) + madd[TheDate.getMonth()] + TheDate.getDate() - 38;
      if (TheDate.getYear() % 4 == 0 && TheDate.getMonth() > 1) {
        total++;
      }
      for (m = 0;; m++) {
        k = (CalendarData[m] < 0xfff) ? 11 : 12;
        for (n = k; n >= 0; n--) {
          if (total < = 29 + GetBit(CalendarData[m], n)) {
            isEnd = true;
            break;
          }
          total = total - 29 - GetBit(CalendarData[m], n);
        }
        if (isEnd) break;
      }
      cYear = 1921 + m;
      cMonth = k - n + 1;
      cDay = total;
      if (k == 12) {
        if (cMonth == Math.floor(CalendarData[m] / 0x10000) + 1) {
          cMonth = 1 - cMonth;
        }
        if (cMonth > Math.floor(CalendarData[m] / 0x10000) + 1) {
          cMonth--;
        }
      }
    }

    function GetcDateString(showYear) {
      var tmp = "";
      if (showYear) {
        tmp += tgString.charAt((cYear - 4) % 10);
        tmp += dzString.charAt((cYear - 4) % 12);
        tmp += "年 ";
      }

      if (cMonth < 1) {
        tmp += "(闰)";
        tmp += monString.charAt(-cMonth - 1);
      } else {
        tmp += monString.charAt(cMonth - 1);
      }
      tmp += "月";
      tmp += (cDay < 11) ? "初" : ((cDay < 20) ? "十" : ((cDay < 30) ? "廿" : "三十"));
      if (cDay % 10 != 0 || cDay == 10) {
        tmp += numString.charAt((cDay - 1) % 10);
      }
      return tmp;
    }

    function GetLunarDay(solarYear, solarMonth, solarDay) {
      if (solarYear < 1921 || solarYear > 2020) {
        return "";
      } else {
        solarMonth = (parseInt(solarMonth) > 0) ? (solarMonth - 1) : 11;
        e2c(solarYear, solarMonth, solarDay);
        return GetcDateString(showYear);
      }
    }

    if (!d) {
      var d = new Date();
    }
    return GetLunarDay(d.getFullYear(), d.getMonth() + 1, d.getDate());
  }

  return this;
}();

//alert(DateUtil.getLunarDay(null)) //当天的农历日期

//alert(DateUtil.getLunarDay(new Date("1988-02-06"))) //腊月十九

//alert(DateUtil.getLunarDay(new Date("1988-02-06"), true)) //丁卯年 腊月十九

原址:gitcode

标签:

相关推荐
更多

飞哥的健身语录
Posted on 08月15日
测试图像格式post
Posted on 09月07日
258集团最新LOGO
Posted on 11月09日
去年今日 你懂的
Posted on 07月13日
  1. Anthonycob 2017-11-10 16:41 #1

    This is nicely put. .
    canadianpharmaciesbnt.com
    canadian drug

  2. 健康网 2017-10-26 07:21 #2

    学海无涯,博客有道!拜读咯!

  3. 套图网 2017-10-25 10:38 #3

    不止一次的来,不止一次的去,来来去去,这就是这个博客的魅力!

  4. 套图网 2017-10-20 07:52 #4

    阅读博客获得的进步不亚于阅读一本书。

  5. 韭菜韭菜 2017-10-20 01:25 #5

    网站不错!!!!